Rabu, 29 Agustus 2012

Matematika " Eliminasi Hp "


Contoh soal mengenai Eliminasi

No. 1
3x – y + 4z = 8.... (1)
5x + y + 2z =12.... (2)
2x + 2y + 3z =14.... (3)

eliminasi (1) dan (2) => hilangkan variabel y
  1. 3x – y + 4z = 8
  2. 5x + y + 2z = 12+

8x + 6z = 20.... (4)

eliminasi (1) dan (3) => hilangkan variabel y
  1. 3x – y + 4z = 8 . 2 =>6x – 2y + 8z = 16
  2. 2x + 2y + 3z = 14 . 1 =>2x + 2y + 3z = 14

8x + 11z = 30.... (5)

eliminasi (4) dan (5) => hilangkan variabel x
  1. 8x + 6z = 20
  2. 8x + 11z = 30 +
    5z = -10
                   z = 2

subsitusi z = 2 ke (4)
8x + 6z = 20
8x + 6(2) = 20
8x + 12= 20
8x = 20 – 12
8x = 8
x = 1

subsitusi x= 1 dan z = 2 ke (1)
3x – y + 4z = 8
3(1) – y + 4(2) = 8
3 – y + 8 = 8
11 – y = 8
-y = 8 – 11
-y = -3
y = 3

Jadi, Hp = { 1, 3, 2 }